SOLVED: Problem 4: The Cantor set C is defined as follows. Remove the middle third, i.e. the interval (1/3,2/3), from the segment [0,1] obtaining the set C1 which consists of the two closed intervals [0, 1/3] and [2/3,1]. Next, remove the middle third part of these two intervals, leaving C2 = [0,1/9] U [2/9,3/9] U [6/9, 7/9] U [8/9,1] and so on. Now consider Cn = 40n1. For the function f(x) = Ic(z) x, compute f dp; [0,1] where p = m 02/9 is the sum of the Lebesgue measure and the Dirac measu

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